3x^2+5x-6.25=0

Solution for 3x^2+5x-6.25=0 equation:

3x^2+5x-6.25=0

a = 3; b = 5; c = -6.25;
Δ = b2-4ac
Δ = 52-4·3·(-6.25)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-10}{2*3}=\frac{-15}{6}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+10}{2*3}=\frac{5}{6}
=5/6
$